Tag: angularjs
Nabin Nepal (Starx) angularjs css html jquery
September 14, 2016

relative position and left and right property together not working, only left is working

Ua_boaz’s Question:

ua_boazua_boaz

I am using this tree grid directive github.com, and below css is taken directly from this library.

.tree-grid .level-2 .indented {
    position : relative;
    left     : 20px;
}

<td><a ng-click="user_clicks_branch(row.branch)"><i ng-class="row.tree_icon" ng-click="row.branch.expanded = !row.branch.expanded" class="indented tree-icon"></i></a><span class="indented tree-label tree-grid-row level-2>
             Citi Corporate and Investment Banking</span>
            </td>

The problem i am having is that span inside td is overflow and showing in the next column, for that purpose i need to add right:20px, but it is not working.

Is there any solution to this problem
plnkr.co

StarxStarx

Just adding padding-right: 20px; gives what you are asking.

I selected the targeted span from CSS like 

<!DOCTYPE html>
<html ng-app="abas-web">
  ...
  <body>
  ...
  <style>
    span.indented.tree-label {
      padding-right: 20px;
    }
  </style>
  </body>

</html>

Demo

Nabin Nepal (Starx) angularjs javascript
April 8, 2016

javascript switch statement/case expression

RGdent’s Question:

RGdentRGdent

I am using a switch statement to search for undefined values to manually change it. but I am having trouble using boolean expressions as I would when using an if statement.

Like: if statemant

if(Item1 == undefined)
{
  item1 ="No";
}
else if (Item2 == undefined)
{
  item2 = "No";
}

etc..

I tried this with the switch statement:

 switch (array) {
 case (item1 == undefined):
 item1 = "No";
 console.log('item1 result', item1 );
 break;
 case item2 == undefined:
 item2 = "No";
 console.log('item2 result', item2 );
 break;
 default:

 }

It does not run through the switch statement, except for when I remove == undefined and only use item1. then it works?

StarxStarx

The switch cannot evaluate values of the array like that and that is why it does not run through the switch statement. You need to define which value of that array you want to switch.

Inside case statement you also cannot use expression, you have to use a value there as well.

So, if you are dead set on using switch for what you are trying to accomplish, you can do something like this:

item1 = array[1];
switch(item1) {
    case "undefined":
        // so on
    break;
}

But, based on your example you are probably trying to check if the values are set or not, for that if statements are still the best choice rather than switch.

$arr = []; // Your array
if(typeof $arr[0] == "undefined") {
    $arr[0] = "No";
}
...

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