August 31, 2015

Checking if an instance's class implements an interface?

Wilco’s Question:

Given a class instance, is it possible to determine if it implements a particular interface? As far as I know, there isn’t a built-in function to do this directly. What options do I have (if any)?

interface IInterface

class TheClass implements IInterface

$cls = new TheClass();
if ($cls instanceof IInterface)
    echo "yes"

You can use the “instanceof” operator. To use it, the left operand is a class instance and the right operand is an interface. It returns true if the object implements a particular interface.

You can also do the following

public function yourMethod(YourInterface $objectSupposedToBeImplementing) {

It will throw an recoverable error if the $objectSupposedToBeImplementing does not implement YourInterface Interface.

Author: Nabin Nepal (Starx)

Hello, I am Nabin Nepal and you can call me Starx. This is my blog where write about my life and my involvements. I am a Software Developer, A Cyclist and a Realist. I hope you will find my blog interesting. Follow me on Google+


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