Context: I’m building a bootstrap class for my PHP Framework, and realized that there are multiple solutions to this security issue.
After researching and reading posts like the one I mentioned at first and others related to htaccess, I think that there are basically three types of solutions:
1 – Checking a constant (like in the post I linked)
if(!defined('THIS_IS_NOT_A_DIRECT_ACCESS')) {
header('HTTP/1.1 404 Not Found');
include('./../error/404.php');
die;
}
I cannot figure out what is wrong with my dropdown menu. When I over over the main level link, the drop down appear but at the left of my screen instead of underneath the main link.
I have been on this for a couple of hours and any help would be greatly appreciated.
I’m struggling to write this myself so I will say what I know I need to do and what I have already.
Based on two $_GET[] variables I need to query a database. The values provide me with the table name and the name of the location. From this location field name, I need to extrapolate the whole row.
So, I query the database with this data, however when I try and fetch and print it nothing happens. I need the whole row’s data (in an array?).
I understand my code is ugly. And probably vulnerable to MySQL injection, but I would rather get my PHP right in terms of getting the row into an array before I worry about that.
It is by design. Apache will not parse PHP code inside a HTML file by default. You can include HTML codes in a PHP file as you would code them in a HTML document.
Renames your files and add extension .php at the end they will parsed as you want.
i just setup a jsfiddle in this link and the problem is where i empty textarea one line break stay and i cant see placeholder again and i always one break line is there see this fiddle
Eperimenting PHP just for fun, But As being newbie, I’m unable to understand curcial parts of PHP….Please help me to sort out this problem which I’m explaining by example :
Suppose
$sql = "SELECT id, text,uid FROM feeds WHERE uid='".$ud."' LIMIT 10";
$items = mysql_query($sql);
echo mysql_error();
if (@mysql_num_rows($items) > 0)
{
while ($item = mysql_fetch_array($items))
{
$feed = $item[1];
$nick = getnick($item[2]);
}
}
So I want to display like this :
3 Records with uid details…
jay,vicky, sumair and 17 others like this.
Please help me to get output of something like this !!
QUESTION: My h3 tag is the most important (for SEO). All 3 have the same indent so I don’t want those changed in any way. If you can help me, what I need to know is:
Since h1 is seen by SEs as most important, am I allowed to rename my current h3 into h1 and vice versa, so that they are in this
order? …
h3
h2
h1
…OR does h1 always have to be “first” in the crawl? Basically I want to tell Google etc that my current h3 is far more important than my current h1 & h2.
