How do i hide html until its processed with javascript?
Question by acidzombie24
I am using some JS code to transform my menu into a drilldown menu.
The problem is before it runs the JS you see a BIG UGLY mess of links. On their site its solved by putting the js at the top. Using recommendations by yahoo/YSlow i am keeping the JS files at the bottom.
I tried hiding the menu with display:none then using jquery to .show(), .css(‘display’, ”), .css(‘display’, ‘block’) and they all lead up to a messsed up looking menu (i get the title but not the title background color or any links of the menu)
How do i properly hide a div/menu and show it after being rendered?
Answer by acidzombie24
I found the solution. I should let the links be hidden with css then .show() BEFORE the ddMenu code executes instead of after. The ddMenu seems to check the parents width and sinces its hidden i guess its 0. The time between .show() and ddMenu is fast enough not to show the ugly links (on my machine/browser). The the majority of the time (page loading, http req for the JS files, JS compiling/exec etc) the links are hidden so it looks pretty good.
$(function () {
$('.menuT1').show(); //do it before not after in this case.
$('.menuT1 > ul').ddMenu({
Answer by Starx
Well, If you are familiar with jquery then I would do something like this
$("#mybuttom").click(function() {
$("#mydiv").hide(); //hide the div at the start of process
$.post( "mypostpage.php",
{ testvar: testdata },
function(data) {
//callback function after successful post
$('#mydiv').show(); //show it again
}
);
});
