Hi! I’m Starx

Question 1

Question by Alwayz Change

My problem is that i wanna use post data outside it’s function, example:

$(function() {
  var s = 'something ';
  $.post('ajax.php', {option: 'test'}, function(data) {
    s += data; // data: 'hello world';
  });
  alert(s); // output: 'something ';
});

my expected result is ‘something hello world’.
how can i deal with this?
Thanks

Answer

Answer by Nishant

Nishant

Use $.ajax with async:false, I assume the data is coming as content-type:json/application e.g.

var s = 'something ';
$.ajax({
      url: "ajax.php",
      type: "POST",
      data: ({option: 'test'}),
      dataType: "json",
      async:false,
      success: function(msg){
         s += msg.data;//msg={data: "hello world"}
      }
   }
);
alert(s);

Answer

Answer by Starx

Starx

You code should be working. Unless the ajax.php is not echoing “Hello World” at the end. Please make sure of it and try to post the results. Errors or output, whatever you can feed us.

Question 2

Question by Crays

Crays

i’m pretty new to this and not sure how should i do it,

I’ve got a database with a column called “names”

how can i make it display in so?

  <tr>
  <td width="270px">Henry</td>
  <td width="270px">Jeffrey</td>
  <td width="270px">Hansel</td>
  </tr>

  <tr>
  <td width="270px">Michelle</td>
  <td width="270px">Jackson</td>
  <td width="270px">Ivan</td>
  </tr>

I only know how i should do it if the records goes one after another vertically.

  $result = mysql_query('SELECT * FROM member');

  while($row = mysql_fetch_array($result))
  {
  echo'
  <tr>
  <td width="270px">'.$row['names'].'</td>
  <td width="270px">Jeffrey</td>
  <td width="270px">Hansel</td>
  </tr>';

Kinda stucked here…

Sorry i forgot to put this.

what i want is that it should loop the tags along. So i can have a 3 column table with infinite rows.

what bout this one? What if i want this to loop instead?

<tr>
<td><img src="images/ava/A.png" /></td>
<td>A</td>
<td width="2px" rowspan="3"></td>
<td><img src="images/ava/B.png" /></td>
<td>B</td>
</tr>


<tr>
<td>A</td>
<td>B</td>
</tr>

Answer

Answer by ascii-lime

ascii-lime

$row will update on each iteration of the loop:

$result = mysql_query('SELECT * FROM member');

echo '<tr>';

for($i = 0; $row = mysql_fetch_array($result); $i = ($i+1)%3){
    echo '<td width="270px">'.$row['names'].'</td>';
    if($i == 2)
        echo '</tr><tr>';
}

echo '</tr>';

Answer

Answer by Starx

Starx

You know accomplish this by assigning the row count before you start the variable and few flags to know initialized loop or started/ended loop.

$i = 1;
$initFlag = false;
$flag = "closed";
while($row = mysql_fetch_array($result)) {
    if($i%3 == 0) $initFlag = false;
    if($flag == "closed" && ($i == 1 || $i % 3 == 1)) { 
        echo "<tr>"; $flag = "started"; $initFlag = true; 
    }

    echo '<td width="270px">'.$row['names'].'</td>';

    if(!initFlag && $flag == "started" && $i % 3 ==0) { 
        echo "</tr>"; $flag = "closed"; 
    }


    $i++;
}

Question 3

Question by winchendonsprings

winchendonsprings

I have 7 divs in a row with all very little content. I want to have the first 3 one a line then the next 3, and so on.

<div class="parent">
 <div class="child-a">abc</div>
 <div class="child-b">def</div>
 <div class="child-c">ghi</div>
 <div class="child-d">jkl</div>
 <div class="child-e">mno</div>
 <div class="child-f">pqr</div>
 <div class="child-g">stu</div>
</div>

So how can I make this work?

For the first line I have

.child-a, .child-b, .child-c {
  padding: 0 2% 0 0;
  width:100%
  display: inline;
  float: left;
 }

What would the css be for child-c, child-d, child-e so that they would be displayed below child-a, child-b, child-c rather than on the same line?

My complete code: http://jsfiddle.net/winchendonsprings/UfswL/11/

Answer

Answer by Starx

Starx

A better way to go would be something like this.

.parent div { float: left; }
.parent div:nth-child(3n + 1) { clear: left; }

Every element after the third will go to next line. Demo

This is do what you asked the first 3 one a line then the next 3, and so on. efficiently despites some browsers compatiblity issues.

Question 4

Question by tonycanyouhearme

tonycanyouhearme

We have 2 applications: web-based (PHP) and Desktop (VB) sharing the same database (Hostgator). Our web app has a fast access to the database (it’s localhost). Our desktop application suffers with slow access and frequent timeouts.
What’s the best approach to this kind of issue? Should we share a database? Are there any other solution.
Thanks

Answer

Answer by Starx

Starx

AFAIK, I dont suppose, this could be a problem. Because, web or desktop, both access the database with MySQL server, so it mustn’t be giving mixed performance results.

Question 5

Question by elduderino

elduderino

Possible Duplicate:
Auto Submitting a form (cURL)

I have a form which submits to a php script. In this form I need to collect all the $_POST data and then post this on to another form (the reason for this isn’t really relevant but there is a good reason).

My question is once I’ve collected all the data from the initial form submit, sanitised it and assigned it all to variables how do i then package it all up to send to the next form? The second form is expecting a $_POST with hidden fields with particular name attributes….so how do i do this? do I build the actual html and submit that somehow to the second form or do I buld some sort of array and send that?

hope this makes sense. Kind of hard to put in to words.

Answer

Answer by RiaD

RiaD

You can generate form and submit onLoad by Javascript
You can use curl to send POST query (from your server but not from client)

Answer

Answer by Starx

Starx

The better way woudl be to store the sanitized variables in the session.

Collect all the information you need from all the forms you need.

Then after you have all the data needed, then finally update the DB (or Somethign else)

Question 6

Question by Shivan Raptor

Shivan Raptor

I would like to add a DIV layer (scrolling according to the position of hyperlink) just like the tooltip of hyperlink, but it shows when page loads, on left top of each hyperlink in a PHP-generated HTML link using CSS & PHP.

How can I achieve this?

Answer

Answer by Starx

Starx

Ok, you can do something like this.

Question 7

Question by Jaggu

Jaggu

Which is the best file upload plugin available for jquery? I’ve read many problems occur with uploadify (the session id, etc) is not passed and it is not so much interoperable with SSL. If this is true which is the best file upload plugin for jquery?

Thanks in advance:)

Answer

Answer by Starx

Starx

If Uploadify is giving you problem, may be you would like to try SWF Upload.

Question 8

Question by Simpanoz

Simpanoz

I have following class for a form:

class Application_Form_ContactForm extends Zend_Form
{
    public function init()
    {
      $this->setName('contact_us');
     /* 
       I have also used follwing statements (one by one) to set name attribute 
       // $this->setAttrib('name', 'myForm-name');
       // $this->setAttribs(array('name' => 'frm', 'id' => 'frmlogin')); 
     */
    }
}

When I run this form, I get follwoing html code:

<form id="contact_us" enctype="application/x-www-form-urlencoded" action="" method="post"><dl class="zend_form">

The above mentioned html code doesn’t show ‘name’ attribute of the form html tag.

Can some one guide me in this regards, how to rectify it.

Answer

Answer by Starx

Starx

The “name” attribute is allowed in HTML4 but has been deprecated in XHTML1.0. The HTML specification does not allow for a “name” attribute for forms. Check Here and here.

Zend Framework is just following the rules.

But why do you need a name is form anyway? Almost everything can be done using class and id.

But, if you really need it that bad try setting a ID first and then the name, it might work.

Question 9

Question by acidpaul

acidpaul

I’m developing a search functionality with pagination in my site to search for the product name and the brand name. I’m using this query to get the user’s search request:

SELECT *
from products
WHERE name = 'optimum nutrition'
    OR brand = 'optimum nutrition' 
    OR name LIKE '%optimum%' 
    OR brand LIKE '%optimum%' 
    OR name LIKE '%nutrition%' 
    OR brand LIKE '%nutrition%'

I would like to display first the products that has the full ‘optimum nutrition’ in either the brand name and in the product name. How will I accomplish this?

Any suggestion would be greatly appreciated.

Answer

Answer by Shef

Shef

Try:

SELECT *, 
CASE WHEN (name = 'optimum nutrition' OR brand = 'optimum nutrition') THEN 1 ELSE 0 END AS full_match,
CASE WHEN (name LIKE '%optimum%' OR brand LIKE '%optimum%' OR name LIKE '%nutrition%' OR brand LIKE '%nutrition%') THEN 1 ELSE 0 END AS half_match
FROM products 
WHERE (name = 'optimum nutrition' OR brand = 'optimum nutrition')
OR (name LIKE '%optimum%' OR brand LIKE '%optimum%' OR name LIKE '%nutrition%' OR brand LIKE '%nutrition%')
ORDER BY full_match, half_match

Answer

Answer by Starx

Starx

I will suggest you look into
Zend Search Lucene, to put search functionality on your page.

Question 10

Question by user667429

user667429

I used two image tags in one div tag. I tried to give different style with css to image tags, so that tags did not any class or id.
but I did not result.
Please correct my css

I used css like this :

div img { padding-right: 2px; vertical-align: middle; }
div img img { width: 16px; height: 16px; }

<div>
<img src="..." alt="" />
<img src="..." alt="" />
</div>

Answer

Answer by spliter

spliter

Second line should be

div img + img { width: 16px; height: 16px; }

Child selector (+) is supported by all contemporary browsers while :last-child in IE is supported by IE9 and up only. IE6 is out of the scope no matter how you approach this.

Answer

Answer by Starx

Starx

Write your css like this

div img:first-child {}
div img:last-child {}

If you have more than 2 <img> inside the div use :nth-child(N)

As spliter mentioned, this is not supported by IE8, in this case use adjacent selector like he has showed in his answer.

Hi! I’m Starx

experienced Software Developer. And this is my blog

Blog Page

How to get data from jQuery.post()?

Question by Alwayz Change

Answer by Nishant

Answer by Starx

Mysql fetch array, table results

Question by Crays

Answer by ascii-lime

Answer by Starx

Line break with css

Question by winchendonsprings

Answer by Starx

Shared database desktop/web app

Question by tonycanyouhearme

Answer by Starx

how to submit a form from a php script

Question by elduderino

Answer by RiaD

Answer by Starx

Add a DIV layer on left top of each hyperlink in page using CSS & PHP

Question by Shivan Raptor

Answer by Starx

Which is the best file upload plugin for jquery?

Question by Jaggu

Answer by Starx

Zend Framework: Zend_Form is not including 'name' attribute in form tag

Question by Simpanoz

Answer by Starx

Search functionality with pagination on a website

Question by acidpaul

Answer by Shef

Answer by Starx

Css for tags with any class or id

Question by user667429

Answer by spliter

Answer by Starx

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