April 22, 2012
What is wrong with these PHP scripts in reading JSON?
Question by Newbie
This is the code that I wrote:
$result = $textProc->sentiment($text);
$json_a = json_decode($result, true);
echo $json_a[label];
where $result stores the JSON data.
However, it returns me error:
Warning: json_decode() expects parameter 1 to be string, object given in C:xampp
htdocsaisentiment.php on line 9
Notice: Use of undefined constant label - assumed 'label' in C:xampphtdocs
aisentiment.php on line 11
Solution:
This is the output of var_dump($result):
object(stdClass)#2 (2) { ["value"]=> float(0.63882080795918) ["sent"]=> int(1) }
Sorry, I should have checked this first.
Answer by Starx
Notice: Use of undefined constant label – assumed ‘label’ in
C:xampphtdocs aisentiment.php on line 11
On echo $json_a[label]; label refers to a constant which is not present.
To refer to an element in a associative array, you have do it as following.
echo $json_a['label'];
Warning: json_decode() expects parameter 1 to be string, object given
in C:xampp htdocsaisentiment.php on line 9
Next, on $result = $textProc->sentiment($text);, The function is not returning a string. Do a var_dump($result) to ensure, it is returning json string format.
