Refer a friend functionallity for a website in OOP
Question by JamesG
I am trying to get to grips with OOP, and just want a little advice on how to approach a problem.
I am making a refer a freind system on my online shop, so when a user registers they will enter an email address of a friend that refered them. This already existing friend then gets a certain amount of points (currency) in their online account.
I have made most of my system just using functions and procedural programming in PHP, but was wondering if anyone could point me in the right direction to making the refer a friend system in OOP, or even if it is worth building in OOP?
I do understand the basic principles of OOP, but not quite sure how to fully build a program from start to finish using it.
Answer by Starx
Ok, this is what i would do
Class User {
// ....
public function newUser(array $params, $isRefer = false, $referal = null) {
// $params Parameters for new user, like name, address etc
// $isRefer boolean value to trigger referal
// $referal Email of the referer
$newUser = new user_model($params);
//Create a DBO of user, as per the new parameters
if(isReferal) { $referer = $this -> getUserIdByEmail($referal); }
//If is referal, get his id, based on email
$status = $this -> add($newUser); //Add the user
//Add the user
if($status) {
//Once it is success
$referer = new User($referer); //Create a object of referer
$referer -> addPoints(50); // Give bonus point
}
return true; //Indicate the success
}
public fucntion __construct($id = null) {
if($id) {
//create the object
$this -> id = $id;
}
// ....
}
protected function getUserIdByEmail($email) {
//get the id
return $id;
}
protected function addPoints($points) {
//add the points on database table
return true;
}
}
The DBO class might be something similar to this
class UserDBO {
protected $name;
protected $address;
public function __construct(array $params) {
$this -> name = $params['name'];
$this -> address = $params['address'];
}
}
Usage:
$userObj = new User();
$userObj -> newUser(array("name", address"), true, "referal@email.com");
