Replacing comma with & before the last word in string
AlexB’s Question:
Having little trouble with what should ideally be a simple thing to accomplish.
What I am trying to do is to replace ', ' before the last word with &.
So basically if word in $ddd exist than need it as & DDD and if $ddd is empty than & CCC
Theoretically speaking, what i do need to acive is the following:
“AAA, BBB, CCC & DDD” when all 4 words are not empty
“AAA, BBB & CCC” when 3 are not empty and last one is
“AAA & BBB” when 2 are not empty and 2 last words are empty
“AAA” when only one is returned non empty.
Here is my script
$aaa = "AAA";
$bbb = ", BBB";
$ccc = ", CCC";
$ddd = ", DDD";
$line_for = $aaa.$bbb.$ccc.$ddd;
$wordarray = explode(', ', $line_for);
if (count($wordarray) > 1 ) {
$wordarray[count($wordarray)-1] = '& '.($wordarray[count($wordarray)-1]);
$line_for = implode(', ', $wordarray);
}
Please do not judge me, since this is just an attempt to create something that I have tried to describe above.
Please help
I think this is the best way to do it:
function replace_last($haystack, $needle, $with) {
$pos = strrpos($haystack, $needle);
if($pos !== FALSE)
{
$haystack = substr_replace($haystack, $with, $pos, strlen($needle));
}
return $haystack;
}
and now you can use it like that:
$string = "AAA, BBB, CCC, DDD, EEE";
$replaced = replace_last($string, ', ', ' & ');
echo $replaced.'<br>';
Here is another way:
$str = "A, B, C, D, E";
$pos = strrpos($str, ","); //Calculate the last position of the ","
if($pos) $str = substr_replace ( $str , " & " , $pos , 1); //Replace it with "&"
// ^ This will check if the word is only of one word.
For those who like to copy function, here is one 🙂
function replace_last($haystack, $needle, $with) {
$pos = strrpos($haystack, $needle);
return $pos !== false ? substr_replace($haystack, $with, $pos, strlen($needle)) : $haystack;
}
