Echo an array from another PHP file
Question by Curtis
I’m currently stuck on what I thought would be an easy solution… I’m working with PHPFileNavigator, and the only thing I’m stuck on is how I can echo the Title that is returned to an array on a separate file. Every time a file is created/edited for an uploaded file, it generates the following file below when a title is added to the file.
Update
Generally all I’m wanting to do is return the one Array value from my destination file which in this case would be from the ‘titulo’ key, and then print it back to my source file.
Destination File
<?php
defined('OK') or die();
return array(
'titulo' => 'Annual 2011 Report',
'usuario' => 'admin'
);
?>
Source File
<?php
$filepath="where_my_destination_file_sits";
define('OK', True); $c = include_once($filepath); print_r($c);
?>
Current Result
Array ( [titulo] => Annual 2011 Report [usuario] => admin )
Proposed Result
Annual 2011 Report
All I’m wanting to find out is how can I echo this array into a variable on another PHP page? Thanks in advance.
Answer by Starx
If you know the file name and file path, you can easily capture the returned construct of the php file, to a file.
Here is an example:
$filepath = 'path/to/phpfile.php';
$array = include($filepath); //This will capture the array
var_dump($array);
Another example of include and return working together: [Source: php.net]
return.php
<?php
$var = 'PHP';
return $var;
?>
noreturn.php
<?php
$var = 'PHP';
?>
testreturns.php
<?php
$foo = include 'return.php';
echo $foo; // prints 'PHP'
$bar = include 'noreturn.php';
echo $bar; // prints 1
?>
Update
To only print a item from the array, you can use the indices. In your case:
<?php
$filepath="where_my_destination_file_sits";
define('OK', True); $c = include_once($filepath); print_r($c);
echo $c['titulo']; // print only the title
?>
