March 23, 2012

Copy file from remote server or URL

Question by Kris

I have the following code:

    $file = '';
    $newfile = '/img/submitted/yoyo.jpg';

    if ( copy($file, $newfile) ) {
        echo "Copy success!";
        echo "Copy failed.";

and it always output “Copy failed”

copy(/img/submitted/yoyo.jpg) [function.copy]: failed to open stream: No such file or directory

my directory is set to 777.

any ideas? thanks!

Answer by Mark Biek

While copy() will accept a URL as the source argument, it may be having issues a url for the destination.

Have you tried specifying the full filesystem path to the output file? I’m assuming you’re not trying to put the new file onto a remote server.

For example:

$file = '';
$newfile = $_SERVER['DOCUMENT_ROOT'] . '/img/submitted/yoyo.jpg';

if ( copy($file, $newfile) ) {
    echo "Copy success!";
    echo "Copy failed.";

The above worked nicely for me.

Answer by Starx

You cannot copy a file from a server without having access to it.

You can ftp_get() to open up a FTP connection and copy file.

$local_file = ''; // the nam
$server_file = '';
$conn = ftp_connect($ftp_server);

$login_result = ftp_login($conn, $ftp_user_name, $ftp_user_pass);

if (ftp_get($conn, $local_file, $server_file, FTP_BINARY)) {
    echo "Successfully copied";

If you want to download a file from URL

$fullPath = "filepath.pdf";

if ($fd = fopen ($fullPath, "r")) {
    $fsize = filesize($fullPath);
    $path_parts = pathinfo($fullPath);
    $ext = strtolower($path_parts["extension"]);
    header("Content-type: application/octet-stream");
    header("Content-Disposition: filename="".$path_parts["basename"].""");
    header("Content-length: $fsize");
    header("Cache-control: private"); //use this to open files directly
    while(!feof($fd)) {
        $buffer = fread($fd, 2048);
        echo $buffer;
fclose ($fd);

Author: Nabin Nepal (Starx)

Hello, I am Nabin Nepal and you can call me Starx. This is my blog where write about my life and my involvements. I am a Software Developer, A Cyclist and a Realist. I hope you will find my blog interesting. Follow me on Google+


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