March 22, 2012
Get the site status – up or down
Question by john
<?php
$host = 'http://google.com';
if($socket =@ fsockopen($host, 80, $errno, $errstr, 30)) {
echo 'online!';
fclose($socket);
} else {
echo 'offline.';
?>
I’m using the above program to get the status of site. But I always get an offline message.
Is there any mistake with the code?
Answer by stewe
The hostname does not contain http://, that is only the scheme for an URI.
Remove it and try this:
<?php
$host = 'google.com';
if($socket =@ fsockopen($host, 80, $errno, $errstr, 30)) {
echo 'online!';
fclose($socket);
} else {
echo 'offline.';
}
?>
Answer by Starx
What about a curl solution?
function checkOnline($domain) {
$curlInit = curl_init($domain);
curl_setopt($curlInit,CURLOPT_CONNECTTIMEOUT,10);
curl_setopt($curlInit,CURLOPT_HEADER,true);
curl_setopt($curlInit,CURLOPT_NOBODY,true);
curl_setopt($curlInit,CURLOPT_RETURNTRANSFER,true);
//get answer
$response = curl_exec($curlInit);
curl_close($curlInit);
if ($response) return true;
return false;
}
if(checkOnline('http://google.com')) { echo "yes"; }
