how to pass array string in javascript function from php end as a argument
Question by Samad
Hey Guys i have a little issue of JavaScript and i don’t know how to solve this Query that why i put this Question in stackoverflow also helps are definitely appreciated
I am getting the error missing ) after argument list in my Firebug console.
My Question is how to pass $char_data variable in JavaScript function as a argument
Define php variable
<?php
$chart_data = "['NBA',1],['NFL',2],['MLB',3],['NHL',4]";
$div = "graph";
?
Call Javascript function with define argument
<script>
dynamicChartArray('<?php echo $div;?>','<?php echo $chartdata;?>')
</script>
A function of javascrpit
<script>
function dynamicChartArray(div,chartdata){
var myData = new Array(chartdata);
var myChart = new JSChart(div, 'pie');
alert(chartdata+div);
}
<script>
Answer by Carl
Rather than creating an array out of a string in javascript, why not just just get the PHP to output it as an array to start with?
Just add an extra set of [] which javascript reads as an array.
$chart_data = "[['NBA',1],['NFL',2],['MLB',3],['NHL',4]]";
then ditch the quotes on the output (which are responsible for causing the error messages)
dynamicChartArray('<?php echo $div;?>', <?php echo $chartdata;?>);
and then myData can just equal chart data (since its already an array)
var myData = chartdata;
Answer by Starx
