March 12, 2012
dynamically creating array in php
Question by vaichidrewar
I am trying to create arrays dynamically and then populate them by constructing array Names using variable but I am getting the following warnings
Warning: in_array() expects parameter 2 to be array, null given
Warning: array_push() expects parameter 1 to be array, null given
For single array this method worked but for array of arrays this is not working. How should this be done?
<?php
for ($i = 1; $i <= 23; ++$i)
{
$word_list[$i] = array("1");
}
for ($i = 1; $i <= 23; ++$i)
{
$word = "abc";
$arrayName = "word_list[" . $i . "]";
if(!in_array($word, ${$arrayName}))
{
array_push($$arrayName , $word);
}
}
?>
Answer by Aleks G
Why are even trying to put array name in a variable and then de-reference that name? Why not just do this:
for ($i = 1; $i <= 23; ++$i)
{
$word = "abc";
$arrayName = "word_list[" . $i . "]";
if(!in_array($word, $word_list[$i]))
{
array_push($word_list[$i] , $word);
}
}
Answer by Starx
And in the for loop, you are accessing the array the wrong way
Here is your corrected code
for ($i = 1; $i <= 23; ++$i)
{
$word = "abc";
$arrayName = $word_list[$i];
if(!in_array($word, $arrayName))
{
array_push($arrayName , $word);
$word_list[$i] = $arrayName;
}
}
