why does jquery's .load() ignore <script>?
Question by Lai Yu-Hsuan
I have a every common page a.html which looks like this:
<html>
<head>
<script type="text/javascript" src="xyz.js" > </script>
</head>
<body>
<div> ... </div>
</body>
</html>
In b.html, I use jquery’s .load()
function to a div
.
$("#myDiv").load("a.html")
It works. The xyz.js’s content is loaded along with a.html. But why isn’t there a <script>
tag? I open firebug to see the source. There is a’s but no a’s <script>
.
I want the <script>
because I need it to find relative path.
(this question)
Edit: I tried to use .get()
and .html()
. Didn’t help.
Edit2: The title is not very appropriate. The xyz.js runs. But no <script>
.
Answer by Pointy
The “.load()” function purposefully strips out <script>
tags from the loaded content. When you give it a plain URL to load, it will execute the scripts after loading the content and adding it to the DOM. However, if you use the trick of adding a selector after the URL in the first argument:
$('#foo').load("http://some.domain.com/blah #special-div");
then it strips the <script>
tags but it does not execute them.
Why? I don’t know.
Now, please note that loading an entire page from the <html>
tag on down into an element of another page is going to result in some sort of Frankenstein monster of a DOM, if a browser will do it at all. Generally, when you use “.load()” to grab fragments of content to update a page, your server should respond with a piece of a page, not the whole thing. The jQuery deal with allowing a selector after the actual URL is intended to let you strip out a chunk of a page, which is really cool, but it has that drawback that the scripts won’t be executed in that case.
Answer by Starx
Because, it cannot run the script inside the <SCRIPT>
tag. jQuery has .getScript()
to call for scripts only. Check here